SOLUTION OF URI 1070 URI SOLUTIONS No comments // 1070 (Mahmud_Jamil) BRUR // Six Odd Numbers #include<stdio.h>int main(){ int i,n; scanf("%d",&n); if(n%2==0) n=n+1; else n=n; printf("%d\n",n); for(i=1;i<=5;i++) printf("%d\n",n+=2); return 0;} Share This: Facebook Twitter Google+ Stumble Digg Email ThisBlogThis!Share to XShare to Facebook Related Posts:SOLUTION OF URI 1156 // 1156 (Mahmud_Jamil) BRUR // S Sequence II #include <stdio.h>int main(){ double a,b=1,c,… Read MoreSOLUTION OF URI 1154 // 1154 (Mahmud_Jamil) BRUR // Ages #include <stdio.h>int main(){ int a,b=0; d… Read MoreSOLUTION OF URI 1151 // 1151 (Mahmud_Jamil) BRUR // Easy Fibonacci #include <stdio.h>int main(){ int x,y, a=0,b=1,c=… Read MoreSOLUTION OF URI 1145 // 1145 (Mahmud_Jamil) BRUR // Logical Sequence 2 #include <stdio.h>int main(){ int X,Y,z,a,b=0… Read MoreSOLUTION OF URI 1131 // 1131 (Mahmud_Jamil) BRUR // Grenais #include <stdio.h>int main(){ int a,b,c=0,d=0,e=0,f,g,h… Read More
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